Computer

Computer related

http://tinyogg.com/

TinyOgg! Watch Flash videos and enjoy freedom

This service allows you to watch and listen to Flash-based videos without the need to Flash technology. This gives you speed, safety, control, freedom and openness.

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http://www.sprixi.com/

Free Image from search engine to use

Sprixi site is one of the best search sites for free photos. It is very fast and provides high quality images and clear distinct from the rest of the other search sites, the site draws Sprixi search results from Flickr pictures and OpenClipArt.org and other sites that allow image review and upload .

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http://www.seppukoo.com/

Another un social networking

This is another un-social networking solution which is focusing on deleting your data and friends from the famous social network Facebook. I think we are witness of a new wave of revolting people who really care about the privacy and social values in the real world.
Seppukoo means in Japanese “let’s make suicide”. I don’t understand this tendency to use such shocking words which I think are not adapted to the situation or the goal of the service. In the blog we presented “suicide machine” and now Seppukoo.
It is a kind of strange to find the same meaning and the same message in these two services. I hope that people don’t take the message as it is and misunderstand that it is a suicide in the virtual world or internet and it does not have any relationship with the real world.

PS: Thanks to Karim for drawing my attention to this service.

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http://www.wolframalpha.com/

Mathematica online

This online service is very useful for people who need complex symbolic mathematics operations.

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Color interpolation in OpenCV

I could not find in Internet a function which can return a RGB color value between two colors So I had to do it myself. I hope it will be useful for someone.

CvScalar interpolate(CvScalar c1, CvScalar c2, double value){
if( value < = 0.0 ){ return c1; }
if( value >= 1.0 ){ return c2; }
int red = cvRound((1.0 - value) * c1.val[2] + value * c2.val[2]);
int green = cvRound((1.0 - value) * c1.val[1] + value * c2.val[1]);
int blue = cvRound((1.0 - value) * c1.val[0] + value * c2.val[0]);
return CV_RGB(red, green, blue);
}

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